Re: [問題] 如何寫成一個猜數字的遊戲
先假設兩個字串length一定為4,字串內數字間沒有重複
輸入輸出就請自己加進去
String stringA = 被猜的數字;
boolean result = false;
while(!result){
String stringB = 輸入猜的數字
int countA = 0;
int countB = 0;
for(int i =0,i<4,++i){
for(int j=0,j<4,++1){
if(stringB.charAt(j)==stringA.charAt(i)){
if(j==i){
countA += 1;
}else{
countB += 1;
}
}
}
}
if(countA == 4){
result = true;
}
}
--
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◆ From: 118.92.243.65
※ 編輯: pelicanper 來自: 118.92.243.65 (10/16 18:35)
推
10/16 18:37, , 1F
10/16 18:37, 1F
→
10/16 22:15, , 2F
10/16 22:15, 2F
→
10/16 22:17, , 3F
10/16 22:17, 3F
→
10/16 22:43, , 4F
10/16 22:43, 4F
→
10/16 22:46, , 5F
10/16 22:46, 5F
推
10/17 00:03, , 6F
10/17 00:03, 6F
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10/17 00:04, , 7F
10/17 00:04, 7F
推
10/17 02:20, , 8F
10/17 02:20, 8F
推
10/17 07:56, , 9F
10/17 07:56, 9F
推
10/17 07:59, , 10F
10/17 07:59, 10F
→
10/17 08:00, , 11F
10/17 08:00, 11F
你是對的...我打錯了~~~
以更正...所以沒有test過的code還是不要亂po
推
10/17 09:14, , 12F
10/17 09:14, 12F
※ 編輯: pelicanper 來自: 118.92.244.103 (10/17 10:27)
※ 編輯: pelicanper 來自: 118.92.244.103 (10/17 10:27)
推
10/17 10:54, , 13F
10/17 10:54, 13F
推
10/18 16:32, , 14F
10/18 16:32, 14F
→
10/19 13:10, , 15F
10/19 13:10, 15F
討論串 (同標題文章)
完整討論串 (本文為第 5 之 7 篇):
問題
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