Pattern pattern = Pattern.compile("href=\"[^\"]*");
Matcher m = pattern.matcher(sb.toString());
while(m.find()) {
String str = m.group();
str = str.replaceFirst("href=\"", "");
str = str.substring(0, str.length()-1);
System.out.println(str);
}
Instead of regular expression,
HTML parser might be the more appropriate and pretty solution.
If you are interested, read this site http://htmlparser.sourceforge.net/
※ 引述《keyairotika.bbs@ptt.cc (空白之才)》之銘言：
> import java.util.regex.*;
> import java.io.*;
> public class Test1 {
> public static void main(String[] args) throws Exception {
> StringBuffer sb = new StringBuffer();
> BufferedReader br = new BufferedReader(new FileReader("c:/work/112.txt"));
> String line="";
> while( (line=br.readLine()) != null) {
> sb.append(line);
> }
> Pattern pattern = Pattern.compile(" "); //裡面要怎麼用才能把我要的網址抽出來?
> Matcher m = pattern.matcher(sb.toString());
> while(m.find()) {
> String str = m.group();
> System.out.println(str);
> }
> }
> }
> 假設在infile.txt裡面有內容如下
> <a class=l href="http://www.ntnu.edu.tw/art/" onmousedown="
> <a class=l href="http://203.71.53.40/" onmousedown="
> <a class=l href="http://www.scdxart.com/" onmousedown="return
> 我只想要裡面的網址如下
> http://www.ntnu.edu.tw/art/
> http://203.71.53.40/
> http://www.scdxart.com/
> Pattern pattern = Pattern.compile(" ");
> 這行裡面要怎麼用
> 我現在只弄到這樣 但還是不對
> Pattern pattern = Pattern.compile("http://[^\"\\s]+");
--
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