[問題] 16QAM解調問題
+3+3j +3+1j +3-3j +3-1j
-3+3j -3+1j -3-3j -3-1j
+1+3j +1+1j +1-3j +1-1j
-1+3j -1+1j -1-3j -1-1j
以上是16QAM的傳輸訊號
Re_compare為實數訊號經過AWGN後,減去傳輸的實數訊號
Im_compare為噓數訊號經過AWGN後,減去傳輸的噓數訊號
為何是以下的判決?
看不懂,想請教一下各位。
麻煩了,謝謝
Re_compare(Re_compare < 1 ) = 0;
Re_compare(1<=Re_compare & Re_compare < 3) = 1;
Re_compare(3<=Re_compare & Re_compare < 5) = 2;
Re_compare(Re_compare > 5) = 1;
Im_compare(Im_compare < 1 ) = 0;
Im_compare(1<= Im_compare & Im_compare < 3) = 1;
Im_compare(3<= Im_compare & Im_compare < 5) = 2;
Im_compare(Im_compare > 5) = 1;
compare_sum1=sum(Re_compare);
compare_sum2=sum(Im_compare);
BER=(compare_sum1+compare_sum2)/(4*sample) %sample為傳輸位元數
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 59.117.70.242
→
03/05 09:39, , 1F
03/05 09:39, 1F
→
03/05 10:38, , 2F
03/05 10:38, 2F
討論串 (同標題文章)