Re: [VB6 ] 如何在PictureBox上用滑鼠點兩點畫線?
※ 引述《cppkiller (cppkiller)》之銘言：
引言恕刪
在下提供兩種寫法 都是由閣下的程式修改而成 也都或有利弊...謹供參考指教
第一種寫法
Dim X1,X2,Y1,Y2,Length as Single
Dim Counter as Boolean
Private Sub Form_Load()
Picture1.DraWidth=10'把設定的東西放在這裡比較好
End Sub
Private Sub Picture1_MouseDown((Button As Integer, Shift As_
Integer, X As Single, Y As Single)
Picture1.Pset(X,Y),RGB(255,0,0)
Counter=Not(Counter)
If Counter Then
X1=X;Y1=Y
Else
X2=X;Y2=Y
End if
End Sub
Private Sub Command1_Click()
Length=Sqr((X1-X2)^2+(Y1-Y2)^2)
Picture1.Line (X1,Y1) - (X2,Y2) , vbBlue
Print Length
End Sub
第二種寫法
Dim X1(1),Y1(1),Length as Single
Dim Counter as Byte
Private Sub Form_Load()
Picture1.DrawWidth=10
End Sub
Private Sub Picture1_MouseDown(Button As Integer, Shift As_
Integer, X As Single, Y As Single)
Picture1.Pset(X,Y),RGB (255,0,0)
Counter=(Counter+1) Mod 2
X1(Counter)=X
Y1(Counter)=Y
End Sub
Private Sub Command1_Click()
Length=Sqr((X1(0)-X1(1))^2+(Y1(0)-Y1(1))^2)
Picture1.Line (X1(0),Y1(0))-(X1(1),Y1(1)),vbBlue
Print Length
End Sub
以耗用資源來說...第一種會比較好....
不過以程式長度和後續仍有使用到XY座標的狀況則是第二種較適用
--
懷抱酸水半滿
若誤子弟無心
一揖還請指教
但望前行提攜
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 219.81.88.26
討論串 (同標題文章)
完整討論串 (本文為第 6 之 6 篇)：