Re: [化學] 中興化學問題

看板TransBioChem作者 (霖)時間13年前 (2011/07/02 21:59), 編輯推噓11(11016)
留言27則, 2人參與, 最新討論串2/2 (看更多)
※ 引述《sparkle0829 (sparkle)》之銘言: : ...... : 98.3. Consider the following chemical reaction: 2A + 2B → C Overall reaction : Reaction mechanism: Step1. A+B→D : Step2. D+B→M : Step3. A+M→C : Which one of the following rate laws is consistent with this mechanism? : (A) Rate = k[A]^2 [B] (B) Rate = k[D][B] (C) Rate = k[A][B] : (D) Rate = k[A] [B]^2 (E) The information is not sufficient : →請問這樣列是錯哪? : Step3: K2 = [M]/[D][B] ; K1 = [D]/[A][B] ; [M]=K2[D][B]=K2K1[A][B]^2 : Rate[C] = K3[A][M] = K1K2K3 [A]^2 [B]^2 我認為是E,不知道哪一部是速率決定步驟~ : 98.6. Gasoline was injected into the cylinder and was ignited. A piston moved : outwardly of the cylinder while exposition took place inside the motor : engine. Which of the following statements is not accurate ? : (A) It is an example of converting chemical energy to mechanical work. : (B) The motor engine had done work to the surrounding. : (C) The temperature dropped down after the piston moved out. : (D) All the energy released from the burning of gasoline was converted : to the work done to the surrounding. : (E) It was an irreversible process. : →是否選E,不可逆表自發,但其被ignite才氣體膨脹? E是對的,答案我認為應該是D。 現實生活中幾乎所有的反應在熱力學夏都是不可逆的(不能回到原本的狀態)。 引擎燃燒爆炸有一大部分的能量變成熱能散失到surrounding, 並沒有全部用來做功! : 98.10. Which of the following statements is wrong about thermodynamics ? : (A) The entropy of any substance(element or compound)in its equilibrium : state approaches zero at the absolute zero of temperature. : (B) The absolute value of the Gibbs free energy of a substance can't : be determined. : (C) The Gibbs free energy is zero during phase transitions of a pure : substance. : (D) The absolute value of the entropy of a substance can't be : determined. : (E) A spontaneous process is always an irreversible process. 我猜是C,相變化自由能會變吧! : 95.29. What is W in Boltzmann's formula, S=k x InW : (A) a fraction indicating the probability of obtaining a result : (B) a random number : (C) the number of ways of obtaining the state : (D) the work times Avogadro's number : →請問這定律是? 應該是A, 普化課本有這個方程式,我記得~ 你可以查看看書本後面的字母索引! : 94.18. If the temperature of the reaction is decreased, what is the effect on : the equilibrium constant and ΔG ? : N2(g) + 3H2(g) → 2NH3(g),ΔH+ = -92.4 kJ/mol : (A) K increases, ΔG increases : (B) K decreases, ΔG decreases : (C) K increases, ΔG decreases : (D) K decreases, ΔG increases : (E) Temperature does not affect equilibrium or ΔG : →請問G是?1. K↑,G= -RTlnK (兩個變因 T↓K↑) : 2. K↑,G= H-TS, T減少到負值,此時G↑ 故選A? K會上升你知道, G的部分我認為這個反應在低溫會趨向自發, 所以溫度越低ΔG應該愈來愈小~ : 94.非選擇題1. Please describe how to set up the physical structure of atom using the : experimental findings. : 題目有點多T_T 今天被教授劣退 有請各位大大幫忙了!感恩!! 抱歉~目前手邊沒有計算紙與筆, 也沒有普化課本, 先回答你這樣, 沒回答的另請高手幫忙~ -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.128.67.245

07/02 23:19, , 1F
98.3=你的想法是對的 不知道哪一步是決定步驟(slow)
07/02 23:19, 1F

07/02 23:20, , 2F
98.10=純物質相變化時自由能變化為零喔 是亂度會變
07/02 23:20, 2F

07/02 23:22, , 3F
所以是D 亂度可以直接求出值
07/02 23:22, 3F

07/02 23:22, , 4F
這年我有考過= = 不過熱化學一年沒碰了大概只記得這些
07/02 23:22, 4F

07/02 23:29, , 5F
水大和v大先謝謝你們 94.18怎麼判斷低溫趨向自發?
07/02 23:29, 5F

07/02 23:34, , 6F
另外亂度 不是要計算系統與環境?不是因為不好測所以才
07/02 23:34, 6F

07/02 23:36, , 7F
改用ΔG只需檢測系統資料 因為環境不知道怎麼測?
07/02 23:36, 7F

07/02 23:45, , 8F
亂度質有公式可以帶
07/02 23:45, 8F

07/02 23:45, , 9F
G(自由能的話) 則只能求出變化量 無法得知其值是多少
07/02 23:45, 9F

07/02 23:47, , 10F
94.18=利用deltaG = deltaH - T x deltaS
07/02 23:47, 10F

07/02 23:47, , 11F
利用deltaG>0可自發<0非自發來判斷
07/02 23:47, 11F

07/02 23:48, , 12F
而T是絕對溫度 故其值必大於零
07/02 23:48, 12F

07/02 23:49, , 13F
所以就可以得知當deltaH>0時 若deltaS也大於零
07/02 23:49, 13F

07/02 23:49, , 14F
了解!
07/02 23:49, 14F

07/02 23:50, , 15F
更正 若deltaS小於零時 算出來deltaG必大於零 自發
07/02 23:50, 15F

07/02 23:50, , 16F
反之就必小於零 非自發
07/02 23:50, 16F

07/02 23:53, , 17F
這題沒給s 是否用S=H/T
07/02 23:53, 17F

07/03 00:10, , 18F
deltaS可以自行判斷 例如液相便氣相會變大之類的
07/03 00:10, 18F

07/03 00:11, , 19F
反應過程中莫耳數變少亂度也是下降
07/03 00:11, 19F

07/03 00:11, , 20F
因此可以得知deltaS<0
07/03 00:11, 20F

07/03 00:17, , 21F
所以ΔS<0 ΔT<0 此G應該為下降了
07/03 00:17, 21F

07/03 00:18, , 22F
可是這題的溫度有改變所以不是用這條公式= =
07/03 00:18, 22F

07/03 00:18, , 23F
不好意思我剛沒注意到
07/03 00:18, 23F

07/03 00:30, , 24F
ΔG=Δ(H-TS)=ΔH-T*ΔS-S*ΔT 我好像越來越模糊了XD
07/03 00:30, 24F

07/03 03:29, , 25F
還是請專家解釋好了XD
07/03 03:29, 25F

07/03 03:30, , 26F
這題我那時候很直接的想K變大deltaG必變更小(負更大)
07/03 03:30, 26F

07/03 03:30, , 27F
剛翻了一下普化還是想不出解釋方式
07/03 03:30, 27F
文章代碼(AID): #1E3oGzgG (TransBioChem)
文章代碼(AID): #1E3oGzgG (TransBioChem)