Re: [問題] 請問卜瓦松機率分配

看板Statistics作者 (路人)時間19年前 (2006/11/21 17:38), 編輯推噓0(000)
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※ 引述《yofute (Henin讚啦)》之銘言: : p(x)=(λ^x*e^-λ)/x!,的E(x)和變異數都是λ : 請問要怎麼分別證明呢? : 我用x=0,1,2.....帶入 x*p(x)化簡,結果算兩個式子就卡住了@@ : 請教各位了^^ 感謝 E[x] = Σxp(x) x = 0~∞ (λ^x)e^(-λ) = Σx------------- x! λ^(x-1) = λe^(-λ)Σ--------- x = 1~∞ , let y = x-1 (x-1)! λ^y = λe^(-λ)Σ---- y = 0~∞ y! = λe^(-λ)e^λ = λ E[x^2] = Σ(x^2)p(x) x = 0~∞ (λ^x)e^(-λ) = Σ(x^2)------------- x! x*e^(-λ)[λ^(x-1)] = λΣ------------------- x = 1~∞ , let y = x-1 (x-1)! (y+1)e^(-λ)(λ^y) = λΣ------------------ y = 0~∞ y! ye^(-λ)(λ^y) e^(-λ)(λ^y) = λ(Σ-------------- + Σ-------------) y! y! = λ(λ+1) Var(x) = E[x^2] - (E[x])^2 = λ(λ+1) - λ^2 = λ # -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 220.129.42.109
文章代碼(AID): #15Oiakmx (Statistics)
文章代碼(AID): #15Oiakmx (Statistics)