Re: [題目] 靜力學
※ 引述《BaBi (迅雷不及掩耳盜鈴)》之銘言:
: [領域] (題目相關領域)
: 靜力學
: [來源] (課本習題、考古題、參考書...)
: Hibbeler 13 Edition Chapter 03
: [題目]
: The single elastic cord ABC is used to supprot the 40-lb load.
: Determine the position x and the tension in the cord that is
: required for equilibrium. The cord passes through the smooth
: ring at B and has an unstretched length of 6 ft and stiffness
: of k = 50 lb/ft
: Figure: http://ppt.cc/z4AW
: [瓶頸] (寫寫自己的想法,方便大家為你解答)
: 如果今天繩子為非彈性繩, 應當是利用繩長關係和相似三角形來求解,
: 但這題為彈性繩, 兩段的繩張力應視伸長量決定, 所以卡關了Orz
我弄出9個未知,7個方程式,還差2個,大家來研究看看
x
左右繩子張力 T1,T2
左右繩子和水平夾角α,β
左右繩子原長 l1,l2
左右繩子增長 Δl1,Δl2
T1 cosα = T2 cosβ
T1 sinα + T2 sinβ = 40lb
l1 + l2 = 6ft
T1 = k Δl1
T2 = k Δl2
cosα = (5-x)/(l1+Δl1)
cosβ = x/(l2+Δl2)
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※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 140.112.251.86
→
03/19 20:25, , 1F
03/19 20:25, 1F
對哦,線變短k會變大
→
03/19 20:26, , 2F
03/19 20:26, 2F
→
03/19 20:28, , 3F
03/19 20:28, 3F
感覺 sin 和 cos 會得到 "恆等式"
※ 編輯: newversion 來自: 140.112.251.86 (03/19 21:04)
→
03/19 21:20, , 4F
03/19 21:20, 4F
→
03/19 21:20, , 5F
03/19 21:20, 5F
→
03/19 21:20, , 6F
03/19 21:20, 6F
討論串 (同標題文章)