Re: [請益] 電路題一問
step 1. 先算出總電流，然後順手整理電路，
I=ε/[(2R//R)+(R//R)]
step 2. 由分流可知各個電阻的電流
I→
┌────┬────┐
│ 2R↓I/3 R↓2I/3
─┴─ε └──┬─┘
┬ ┌──┴─┐
│ R↓I/2 R↓I/2
└────┴────┘
step 3. 回到原圖，由節點定律可知A=I/6 向左
┌────┬────┐
│ 2R↓I/3 R↓2I/3
─┴─ε ├─ A──┤
┬ │ │
│ R↓I/2 R↓I/2
└────┴────┘
step 4. 自己將I置換完就ok
應該沒錯八，這......應該還在課本例題範圍內巴@@|||
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