Re: [請益] 倒晶格向量的推導
※ 引述《h888512 (理論型嘴砲)》之銘言：
: 今天上固物上到倒晶格的部份
: 從傅立葉推到G。T = 2nπ,其中T是primitive cell的晶格向量
: 且T = ad1+bd2+cd3, G = hA1+kA2+lA3
: 然後對任意整數的a,b,c G。T = 2nπ都成立
: 所以 G。d1 = 2π, G。d2 = 2π, G。d3 = 2π也成立
: 到這邊都還沒問題,接下來老師就說因為orthogonality
: 所以A1。d1 = 2π, A1。d2 = 0 , A1。d3 = 0 ===> A1 = c (d2 x d3)
: A2。d1 = 0 , A2。d2 = 2π, A2。d3 = 0 ===> A2 = c (d1 x d3)
(d3 x d1)
: A3。d1 = 0 , A3。d2 = 0 , A3。d3 = 2π ===> A3 = c (d1 x d2),c都是常數
: 上面是怎麼來的阿? Orthogonality是指哪組阿??請大家幫忙解答,感謝!!
A1。(d1 。 d2 x d3) = 2 pi (d2 x d3) and so on
because Omega = (d1 。 d2 x d3) = (d2 。 d3 x d1) = (d3 = d1 x d2)
Omega is Volume of lattice
以上
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