[請益] array values to ...
其實標題不知道怎麼下才好,
如果有人可以指導一下感激不盡 = =
以下是目前所遇到的問題,
假設目前有 3 個 array,
$key_1_arr = array("a", b", "c", "d");
$key_2_arr = array("e", f", "g");
$key_3_arr = array("h", i", "j", "k", "l");
想把它們轉成如下的新 array,
$new_1_arr["a"]["b"]["c"]["d"] = 4; // 4 = count($key_1_arr)
$new_2_arr["e"]["f"]["g"] = 3;
$new_3_arr["h"]["i"]["j"]["k"]["l"] = 5;
不知道有沒有什麼方法可以達成呢?
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 118.168.216.238
→
02/07 13:28, , 1F
02/07 13:28, 1F
→
02/07 13:50, , 2F
02/07 13:50, 2F
→
02/07 13:50, , 3F
02/07 13:50, 3F
→
02/07 15:48, , 4F
02/07 15:48, 4F
→
02/07 15:51, , 5F
02/07 15:51, 5F
→
02/07 16:21, , 6F
02/07 16:21, 6F
→
02/07 16:31, , 7F
02/07 16:31, 7F
→
02/07 18:34, , 8F
02/07 18:34, 8F
推
02/07 22:47, , 9F
02/07 22:47, 9F
→
02/08 01:14, , 10F
02/08 01:14, 10F
→
02/08 01:21, , 11F
02/08 01:21, 11F
→
02/08 01:21, , 12F
02/08 01:21, 12F
→
02/08 01:22, , 13F
02/08 01:22, 13F
→
02/08 01:24, , 14F
02/08 01:24, 14F
→
02/08 01:24, , 15F
02/08 01:24, 15F
→
02/08 01:25, , 16F
02/08 01:25, 16F
→
02/08 01:29, , 17F
02/08 01:29, 17F
→
02/08 01:30, , 18F
02/08 01:30, 18F
→
02/08 01:30, , 19F
02/08 01:30, 19F
→
02/08 01:31, , 20F
02/08 01:31, 20F
→
02/08 01:32, , 21F
02/08 01:32, 21F
→
02/08 01:33, , 22F
02/08 01:33, 22F
→
02/08 01:36, , 23F
02/08 01:36, 23F
→
02/08 01:43, , 24F
02/08 01:43, 24F
→
02/08 01:47, , 25F
02/08 01:47, 25F
討論串 (同標題文章)
以下文章回應了本文:
完整討論串 (本文為第 1 之 3 篇):