Re: [算表] excel計算特殊符號@
※ 引述《wfdlm (指尖的星光)》之銘言:
: 軟體:
: EXCEL 2003 / 2007 版
: ( 以下文章有點長,再加上不專業的敘述 敬請見諒 )
: 背景故事:
: 由於想要從google docs 問卷調查表中直接統計人數
: 為了避免重覆投票(google 問卷似乎沒有防止此項功能)
: 因此想說請投票者填入E-MAIL,以及 "同意" 或 "不同意"
: 問卷回收後 只要 countifs(range,"同意",range,"@")
: 就大膽假設可以直接計算有填 "E-MAIL" 和 "同意" 的人數
: (因為e-mail中都至少有"@"符號,其他的方式我目前也沒有想到 或是無法辦到)
: 可是試了幾次以後,發現無法計算"@" 這樣的符號
: 請問版上高手,如何解決像這樣的問題?
: 或是 如果改填 "身分證字號",以及 "同意" 或 "不同意"
: EXCEL 可以判別這組身分證字號是否有效嗎?
: (google有高手用EXCEL寫身分證產生器,可是不知道有沒有辦法靠語法來辨認)
: 假設可以的話,
: 請問要怎麼計算:有填 "身分證字號" 且 "同意" 的人數呢?
: 感謝看完的人,更感謝大家指教!
=IFERROR(IF(LEN(A1)<>10,"不符",IF(AND(--MID(A1,2,1)<>1,--MID(A1,2,1)<>2),
"不符",IF(MOD(10-MOD(MID(LOOKUP(LEFT(A1,1),{"A","B","C","D","E","F","G",
"H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y",
"Z"},{10,11,12,13,14,15,16,17,34,18,19,20,21,22,35,23,24,25,26,27,28,29,
32,30,31,33}),1,1)*1+MID(LOOKUP(LEFT(A1,1),{"A","B","C","D","E","F","G",
"H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y",
"Z"},{10,11,12,13,14,15,16,17,34,18,19,20,21,22,35,23,24,25,26,27,28,29,
32,30,31,33}),2,1)*9+MID(A1,2,1)*8+MID(A1,3,1)*7+MID(A1,4,1)*6+MID(A1,5,
1)*5+MID(A1,6,1)*4+MID(A1,7,1)*3+MID(A1,8,1)*2+MID(A1,9,1)*1,10),10)=--
RIGHT(A1,1),"符合","不符"))),"不符")
--
just for fun...
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◆ From: 61.216.4.145
※ 編輯: Tenka 來自: 61.216.4.145 (10/16 02:38)
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