[微積] continuous derivative 問題

看板Math作者 (沒有暱稱)時間1月前 (2024/03/21 16:37), 編輯推噓4(408)
留言12則, 6人參與, 1月前最新討論串1/1
Thomas' calculus 關於積分弧長,有先做一個前提: Suppose the curve whose length we want to find is the graph of the function y = f(x) from x= a to x = b. In order to derive an integral formula for the length of the curve, we assume that ƒ has a continuous derivative at every point of [a, b]. Such a function is called smooth,and its graph is a smooth curve because it does not have any breaks, corners, or cusps. 最後說到: (1 + [f'(x)]^2)^1/2 is continuous on [a,b] 想問f has a continuous derivative ... of [a,b]的意思是 (1) f'(x) is continuous on [a,b] 還是 (2) f在[a,b]每一點都有derivative 如果是(2) 舉一個example https://imgur.com/Wv2wDLl
g(x)每一點都有derivative 但是 g'(0)在x = 0 並不連續。 這樣的話 "(1 + [f'(x)]^2)^1/2 is continuous " 就不一定會成立吧? 所以原文的意思是應該是(1)? -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 210.242.38.34 (臺灣) ※ 文章網址: https://www.ptt.cc/bbs/Math/M.1711010274.A.A0B.html

03/21 18:46, 1月前 , 1F
您po的原文敘述有強調是平滑曲線,排除斷點 折角
03/21 18:46, 1F

03/21 18:47, 1月前 , 2F
"not have any breaks, corners or cusps."
03/21 18:47, 2F

03/21 20:33, 1月前 , 3F
所以你認為是(2)?
03/21 20:33, 3F

03/21 20:33, 1月前 , 4F
我的舉例g of x雖然靠近0會劇烈跳動 但應該每個點都
03/21 20:33, 4F

03/21 20:33, 1月前 , 5F
可以微分且g'在0不連續吧 這樣不符合圓滑曲線嗎
03/21 20:33, 5F

03/21 23:06, 1月前 , 6F
這是英文問題不是數學問題,a continuous derivativ
03/21 23:06, 6F

03/21 23:06, 1月前 , 7F
e 的意思是 a derivative that is continuous 也就
03/21 23:06, 7F

03/21 23:06, 1月前 , 8F
是導數是一個連續函數。
03/21 23:06, 8F

03/21 23:12, 1月前 , 9F
就 (1)
03/21 23:12, 9F

03/22 04:19, 1月前 , 10F
我還以為是要問在端點微分是什麼意思XD
03/22 04:19, 10F

03/22 08:39, 1月前 , 11F
好的 謝謝各位
03/22 08:39, 11F

03/22 11:05, 1月前 , 12F
當然是 1,語意蠻明確的
03/22 11:05, 12F
文章代碼(AID): #1b-_7YeB (Math)