Re: [中學]數與數線

看板Math作者 (keith)時間6年前 (2017/09/09 00:54), 編輯推噓0(000)
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※ 引述《adamchi (adamchi)》之銘言: : 1.a,b,c為任一三角形的邊長,證明abc >= (b+c-a)(c+a-b)(a+b-c) Set A = b+c-a, B = c+a-b, C = a+b-c It's equivalent to prove : ( (B + C)/2 )( (C + A)/2 )( (A + B)/2 ) ≧ABC Which is obviously hold by AM-GM inequality. : 2.x>3,當x=___,使得(x+6)/(x-3)^1/2 有最小值,且最小值為____ By AM-GM inequality : (x+6)/(x-3)^1/2 = (x-3+9)/(x-3)^1/2 = √(x-3) + 9/√(x-3) ≧2*√9 = 6 The inequality attains it's minimum 6 at x = 12. -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 36.226.174.2 ※ 文章網址: https://www.ptt.cc/bbs/Math/M.1504889674.A.27E.html
文章代碼(AID): #1PiijA9- (Math)
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文章代碼(AID): #1PiijA9- (Math)