
Re: [微積] 無窮積分一題請教

a = 16.5, n = 5
∫x^a exp(-x^n) dx
(u = x^n)
= (1/n)∫u^(a/n) exp(-u) (u^(1/n))/u du
∞
= (1/n)∫u^((a + 1 - n)/n) exp(-u) du
0
= (1/n) Γ((a + 1)/n)
= (1/5) Γ(3.5)
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