Re: [中學] 三角柱翻轉的問題
: 如圖，兩題求解
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(1)
6 * 8 * (1/2) * 2 = [(8 - h) / 8]^2 * 6 * 8 * 1/2 * 8
=> 16 = (8 - h)^2
=> h = 8 - 4 = 4 另一解不合
(2)
6 * 8 / 10 = 24 / 5
6 * 8 * (1/2) * 2 = [(24/5 - h) / (24/5)]^2 * 6 * 8 * 1/2 * 8
=> 1/4 = [1 - 5h/24]^2
=> h = (24/5) * (1/2)
= 12/5
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※ 編輯: Honor1984 (111.249.190.224), 04/10/2017 00:29:02
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