[微積] Integral problem
b
∫xdx/[(x^2-a^2)(b^2-x^2)]^(1/2)=?
a
題目如上
求解法
參考書只給答案pi/2
但不知其所以然
用了integration by part或代換法還是找不到解法
請各位大大幫忙
感謝
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