Re: [微積] Total diff + Tangent plane
※ 引述《subtropical (風大雨大)》之銘言:
: f: D -> R
: (x,y) -> xy^(1/3) , x>0, y>0
: 求(1,1)的全微分
df = y^(1/3)dx + (1/3)xy^(-2/3)dy
df| = dx + (1/3)dy
(1,1)
: 求(1,1,1)的Tangent plane
z = xy^(1/3)
g(x,y,z) = z - xy^(1/3)
▽‧g| = (-y^(1/3),-(1/3)xy^(-2/3),1)|
(1,1,1) (1,1,1)
= (-1, -1/3, 1)
Tangent plane
-(x-1)-(1/3)(y-1)+(z-1) = 0
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 128.220.147.176
推
06/19 14:32, , 1F
06/19 14:32, 1F
討論串 (同標題文章)
本文引述了以下文章的的內容:
完整討論串 (本文為第 2 之 2 篇):