Re: [中學] 突然有點傻住的問題= =!!
※ 引述《yourfriend (祈禱)》之銘言:
: 有一球以(0,0,0)為球心,r^2=10
: 其中有兩點A(-2,√5,1) B(1,0,3),
: 求A到B最短距離
: 這題好像不難~但我就是忘了= =!!
: 可以麻煩有人可以教一下嗎?謝謝!!
OA.OB = 10 cosθ = -2 + 3 = 1
θ = acos(1/10)
min AB = rθ = √10 acos(1/10)
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※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 123.194.96.239
推
04/21 20:27, , 1F
04/21 20:27, 1F
If A(-2,√5,-1) B(1,0,3)
then OA.OB = 10 cosθ = -2-3=-5
cosθ = -1/2
then θ = 2π/3
min AB = rθ = √10 (2π/3)
※ 編輯: JohnMash 來自: 123.194.96.239 (04/21 20:34)
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