Re: [微積] 高中極限
※ 引述《gagaRicky (Ricky)》之銘言：
: 設an為區間[0，1]不含0的n位小數的個數，sn為這些小數的總和
: 那lim n趨近於無限大 的an/sn是多少
0.111,0.112,...,0.998,0.999
+ 0.999,0.998,...,0.112,0.111
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1.110,1.110,...,1.110,1.110
an = K, sn=1.11...*K/2
K = 9^n
an/sn = 2/1.111... = 2/(10/9) = 9/5 = 1.8
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◆ From: 123.194.96.239
※ 編輯: JohnMash 來自: 123.194.96.239 (04/17 13:22)
推
04/17 14:01, , 1F
04/17 14:01, 1F
推
04/17 14:23, , 2F
04/17 14:23, 2F
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