[代數] 找permutation的degree~
在 Sn 中
隨便給定一個permutation
該如何求出它的degree?
如:
在S_101中,permutation:
( 1 2 3 ... 50 51 52 53 ... 101)
( 1 3 5 ... 99 101 2 4 ... 100)
求其drgree = ?
我的想法是將其拆成 disjoint cycle
再求這些disjoint cycle的degree的最小公倍數,
可是101太大,不知是否有好的辦法將此permutation拆成disjoint cycle?
麻煩高手指點,感激不盡~
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推
05/11 12:51, , 1F
05/11 12:51, 1F
推
05/11 12:53, , 2F
05/11 12:53, 2F
→
05/11 16:15, , 3F
05/11 16:15, 3F
→
05/11 16:15, , 4F
05/11 16:15, 4F
→
05/11 17:20, , 5F
05/11 17:20, 5F
推
05/12 04:05, , 6F
05/12 04:05, 6F
→
05/12 04:06, , 7F
05/12 04:06, 7F
→
05/12 06:29, , 8F
05/12 06:29, 8F
→
05/12 08:08, , 9F
05/12 08:08, 9F
推
05/12 10:57, , 10F
05/12 10:57, 10F
→
05/12 10:58, , 11F
05/12 10:58, 11F
推
05/17 17:42, , 12F
05/17 17:42, 12F
→
08/13 16:51, , 13F
08/13 16:51, 13F
→
09/17 14:47, , 14F
09/17 14:47, 14F
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