第78回 演練題第六題
原題目：甲、乙二人輪擲一不公正銅板(正面機率2/3、反面1/3)，
若出現正面，甲給乙一元；出現反面，乙給甲一元。
今甲有m元，已有n元，則甲將乙錢贏光之機率?
<詳解的解法>
設甲有k元時，將乙錢贏光之機率為a_(k)
=> a_(0)=0 ； a_(m+n)=1
a_(k)=(1/3)a_(k+1) + (2/3)a_(k-1) -------->這句看不太懂，為什麼1/3倍的a_(k+1)
加上 2/3倍的a_(k-1) 會等於a_(k) ???
麻煩各位高手大大了~感激不盡~!!!
或者有什麼比遞迴還漂亮的解法嗎??
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