Re: [微積] 工數 降階
※ 引述《ComeonLuLuLu (盧彥勳加油)》之銘言:
ODE中沒有y出現:
d(y') dp
令y' = dy/dx = p 則 y'' = ------- = -----
dx dx
原ODE f(y'',y',x) = 0 ==> f(p',p,x) =0 ==> 變一階
ODE中沒有x出現:
d(y') d(y') dy d(p)
令y' = dy/dx = p 則 y'' = ------ = ------ ----- = ------ p
dx dy dx dy
dp
原ODE f(y'',y',y) = 0 ==> f(---- p,p,y) =0 ==> 變一階(以y當自變數 ,p當應變數)
dy
dp
ex : y''+y^2 =0 ==> ----p + y^2 = 0
dy
pdp + y^2dy = 0 , p + (1/3)y^3 = C ,記得把p=y' 帶回去再繼續解
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d d dp dy
y''' = ----- (y'') = ----(---- p)---- = ....
dx dy dy dx
※ 編輯: doublewhi 來自: 140.113.122.118 (11/07 18:16)
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