[線代] 矩陣求rank
版友好...有一題矩陣不太懂...煩請板友解惑
2 4 1 -1 2
A=[ -1 -2 3 0 -2 ]
0 0 1 8 -4
0 0 0 -1 1
0 0 0 -4 3
求A的rank.
解答如下:
(-1/2) (4/3)
他 C C 行運算後
2 1 5 4
變成了
0 4 1 5/3 2
A=[ 0 -2 3 -8/3 -2 ]
0 0 1 8/3 -4
0 0 0 1/3 1
0 0 0 0 3
故rank(A)=4..................這是解答
我的問題是...
(1) rank的定義不是 : 矩陣的非零"列"有幾"列" 嗎?
從解答中我看到的是只有一行都是0,但每列都是非全為0列
為什麼解答知道rank是4
(2) 既然想要知道一個矩陣rank,此題為什麼要行運算,不做列運算呢?
這是一個補習班老師的課本的題目,很多人說他工數神父..真的疑惑地睡不著了>_<
感謝板友解答
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