Re: [中學] 97嘉中資優班考題
※ 引述《qpzmm (欽仔)》之銘言：
: 化簡: [4^(1/3)-1]^1/2 + [16^(1/3)-4^(1/3)]^(1/2)
a^3=4 and a>1
a^4=4a
a^2=2√a
K=√(a-1) + √(a^2-a)
=(√a + 1) √(a-1)
K^2 =(√a + 1)^2 (a-1)
=(a+1+2√a)*(a-1)
=(a^2+a+1)(a-1)
=a^3-1=3
K=√3
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 112.104.170.71
→
07/06 22:14, , 1F
07/06 22:14, 1F
討論串 (同標題文章)