[線代] 對角化特徵向量矩陣的行順序跟解

看板Math作者zmack0905 (降太)時間13年前 (2011/04/10 15:40)推噓1(1推 0噓 2→)

留言3則, 3人參與討論串1/1

今有一矩陣 A = [3,2] 特徵值 7 . 2 特徵向量 7 = [1] 2=[ 2] [2,6] [2] [-1] 令矩陣X = [1, 2] X^-1=[0.2, 0.4] [2,-1] [0.4,-0.2] X^-1 * A * X =[7,0] [0,2] 但若將X組成相反 X=[2, 1] 則 X^-1 =[ 0.4,0.2] [-1,2] [-0.2,0.4] X^-1 * A * X = [ 1.2,5.6] [-1.6,4.2] !? 無法將作為對角化矩陣請問是計算錯誤.還是行向量的順序有一定規則?又此規則是? --