Re: [微積] 不定績分
※ 引述《ru18284 (浪子回頭)》之銘言：
: 遇到了困難..
: 各位大大能否幫我解答一下 ^^
: Find a function f and a number a such that
: x
: 6 + ∫ f(t)/ t^2 dt = 2√x
: a
: for all x > 0
: 謝謝囉!!!!!
: 感恩~~
兩邊同時對x微分
f(x)/x^2 = 1/√x
=> f(x) = x^(3/2)
#
let x = a
=> 6 = 2√a
=> a = 9
#
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