http://www.imgtank.com/view-pic.php?img=359
如圖：
假設 AB 長為 a
則 BC = 10 - a (因為大三角形邊長 = 半圓直徑 = 10)
所以正方形邊長是 10 - a (因為上方的小三角形也是正三角形)
(即 BE = 10 - a)
另外，由三角形 ABD 我們可以知道，
√3
BD = ----- * a
2
AD = a/2
所以 OD = 5 - a/2 (O為半圓圓心)
由於 DE^2 = OE^2 - OD^2
(BE-BD)^2 = OE^2 - OD^2
將 BE = 10-a，BD = √3*a/2，OE = 5，OD = 5-a/2 代入可以算出 a
就可以進一步算出正方形邊長
但代入後得到的式子實在很難看
所以看看有沒有人有更好的方式吧
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