[分析] 隱函數定理
(1)Show that x^2-y^2-u^3+v^2+4 = 0
2xy+y^2-2u^2+3v^4+8 = 0
can be solve u, v as continuously differentiable functions of
(x,y) for (x,y) near (2,-1) satisfying u(2,-1)=2, v(2,-1)=1.
(2)Find the value of du dv
----(2,-1) + ----(2,-1)
dx dx
第一小題的部分我會做
但是第二小題想不出辦法解出來 Q Q
懇請各位強者能指示小弟一點方向
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