Re: [機統] 機率,幫解

看板Math作者 (呆)時間13年前 (2011/01/07 10:06), 編輯推噓0(001)
留言1則, 1人參與, 最新討論串3/3 (看更多)
※ 引述《miisoo (味噌)》之銘言: : (1)two cards are randomly selected from an ordinary playing deck. : what is the probability that they form a blackjack? : That is ,the probability that one of the cards is an ace : and the other one either a ten, a jack, a queen,or a king. : (2)compute the probability that a hand of 13 cards contains : (a)the ace and king of some suit : (b)all 4 of at least 1 of the 13 denominations. : 算好久,還是解不出來> <" : 請會的人幫忙解答,謝謝 : 答案(1)0.0483 : (2)a 0.2198 : b 0.0324 2a: 13張牌中有AK同花的機率 分子 4x(一組AK同花) -6x(兩組AK同花) +4x(三組AK同花) -1x(四組AK同花) = 4xC(50,11) -6xC(48,9) +4xC(46,7) -C(44,5) = 139565328072 分母 C(52,13) = 635013559600 機率 0.219783225 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 219.81.148.30

01/08 01:27, , 1F
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01/08 01:27, 1F
文章代碼(AID): #1D9dKFVX (Math)
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文章代碼(AID): #1D9dKFVX (Math)