Re: [閒聊] 每日leetcode已回收

看板Marginalman作者 (smart0eddie)時間1年前 (2024/07/06 09:33), 編輯推噓1(100)
留言1則, 1人參與, 1年前最新討論串452/1554 (看更多)
2024-07-06 2582. Pass the Pillow There are n people standing in a line labeled from 1 to n. The first person in the line is holding a pillow initially. Every second, the person holding the pillow passes it to the next person standing in the line. Once the pillow reaches the end of the line, the direction changes, and people continue passing the pillow in the opposite direction. For example, once the pillow reaches the nth person they pass it to the n - 1th person, then to the n - 2th person and so on. Given the two positive integers n and time, return the index of the person holding the pillow after time seconds. 100%的是用暴力解 - - 這其實是數學問題 走一趟要 n-1 秒 走到底折返 所以先 time / (n-1) 看可以走完奇數趟還偶數趟 奇數反走 偶數正走 然後 time % (n-1) 看要多走幾格 int passThePillow(int n, int time) { int dir = (time / (n - 1)) % 2; int pos = time % (n - 1); if (dir) return n - pos; else return pos + 1; } -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 73.173.211.221 (美國) ※ 文章網址: https://www.ptt.cc/bbs/Marginalman/M.1720229596.A.146.html

07/06 09:36, 1年前 , 1F
大師
07/06 09:36, 1F
文章代碼(AID): #1cY9xS56 (Marginalman)
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文章代碼(AID): #1cY9xS56 (Marginalman)