Re: [閒聊] 如果四隻全部3-3 要怎麼加賽?消失
※ 引述《XianDao (^_^)》之銘言：
: 這個問題我昨天就想過了
: 現在提供你們最佳解
: 就抽籤分組打1場 A打B C打D
: 只要贏了就晉級阿
: 最後再補一場決定第一名
: 總共才加3場而已啊
: 根本超簡單的好不好
: 這個解為最佳解
: 主辦單位想得到的通常比我想的還要爛很多
主辦單位想到的不是抽籤是看時間
6.4.6 Four-way tie.
The teams will be drawn into a single elimination bracket based on the
cumulative game victory time for the individual teams.
Teams play best-of-one matches throughout the bracket.
The seeds will be given in order to the teams that won their games the quickest.
The four teams will be split into two first-round matches;
the #1 seed (i.e. fastest total game victory time) will face
the #4 seed (i.e. slowest total game victory time),
while the #2 seed will face the #3 seed in the first two games.
The losing teams will be eliminated from the tournament.
The winner of Game 3 will be declared the top seed;
the loser of Game 3 will be declared the second seed.
6.4.6.1 Side Selection.
Side selection for all games under this tiebreaker belongs to
the team with the lower total game victory time.
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※ 編輯: lionheart60 (36.230.238.66), 10/15/2018 19:47:40
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