討論串[理工] [工數]向量積分
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b.. r = t i + t^2 j + t^3 k , 故. x = t , y = t^2 , z = t^3. ∫F．dr = ∫e^x dx + e^(4y/x)dy + e^(2z/y) dz. =∫ e^t dt + e^(4t^2/t) d(t^2) + e^(2t^3/t^2) d
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a. r=cos t i + sin t j + t k, 故. x=cos t , y = sin t , z = t. (1,0,0) -> t=0 , (1,0,4 π) -> t=4π. ∫ F．dr = (x^5 dx + x^4y dy + (z^2 x + 2z y) dz. = ∫_
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compute. a. → → → →. F =x^5i +x^4yj +(z^2x+2zy)k. → → → →. r =costi +sintj +tk. from (1,0,0)to (1,0,4pi). 答案 0. b. → → → →. F =e^xi +e^(4y/x)j +e^(2z/
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