
Re: [理工] 萊布尼茲求積分?

: 這題我直接想到用拉式轉換後,再用s代0去解。
: 不過後來老師有說也可以用萊布尼茲去解,請問這要怎麼用萊布尼茲解啊?
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: Sent from JPTT on my iPhone
以萊布尼茲命名的很多
是萊布尼茲的什麼要講清楚
∞
F(a) = ∫ sin(ax)/x dx
0
∞
= (1/2)∫ sin(ax)/x dx
-∞
∞
F'(a) = ∫cos(ax) dx
0
= πδ(a)
=> F(a) = πu(a) + C
F(a) = -F(-a)
=> πu(a) + C = -πu(-a) - C
=> C = -π/2
所以
原積分 = π - π/2
= π/2
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