
Re: [理工] 103 清大資工 離散

: 想請教各位大大
: 看了解答之後
: 題目的(mod m)是用來幹嘛的QQ
: 感覺好像沒有甚麼用處阿
n為整數
a_(n-1) = (n-1)! (mod m)
=> na_(n-1) = n[(n-1)!] (mod m)
=> na_(n-1) = n! (mod m)
又因為a_n = n! (mod m)
=> a_n = na_(n-1) (mod m) for n >= 2
因為a_1 = 1 (mod m)
可令a_0 = 1
使a_n = na_(n-1) (mod m) for n >= 1
--
※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 61.56.10.14
※ 文章網址: https://www.ptt.cc/bbs/Grad-ProbAsk/M.1489733773.A.F9C.html
→
03/17 16:06, , 1F
03/17 16:06, 1F
→
03/18 01:16, , 2F
03/18 01:16, 2F
推
03/18 23:57, , 3F
03/18 23:57, 3F
→
03/18 23:57, , 4F
03/18 23:57, 4F
→
03/19 02:44, , 5F
03/19 02:44, 5F
→
03/19 02:45, , 6F
03/19 02:45, 6F
討論串 (同標題文章)