Re: [理工] 高等工數有關熱對流

看板Grad-ProbAsk作者 (TOEFL_5!)時間8年前 (2015/10/13 23:18), 編輯推噓2(202)
留言4則, 3人參與, 最新討論串2/2 (看更多)
※ 引述《cyc647 (小G)》之銘言: : 代PO,不妥請告知刪文 : A solid cylinder.0<r<b,0<z<c,is initially at temperature F(r,z).For times : t>0,the boundary at z=0 is insulated, the boundary at z=c is dissipating heat : by convection into a medium at zero temperature, and the boundary at r=b is : kept at zero temperature. Obtain an expression for the temperature : distribution T(r,z,t) in the solid for times t>0. : 本題是求溫度T(r,z,t),應該是用PDE : 同學完全不知道如何下手 : 有大大知道怎麼解嗎???? Heat conduction problem r=b kept zero temprature z=0 was insulated z=c was cooling by convection of the surroundings Laplacian T = k dT/dt With the axial-symmetric polar coordinate description d^2T/dr^2+1/r*dT/dr = k dT/dt I.C.s T(r,z,0)=F(r,z) B.C.s dT/dr = 0 where z=0 (no heat flux passing) T =0 where r= b (zero temprature) Newton cooling law (dQ/dt = h (T-Ts)) h is convecton coefficient and Ts is temprature of surroundings Let you try __ -- posted from bbs reader hybrid on my Sony C6903 -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 42.79.87.133 ※ 文章網址: https://www.ptt.cc/bbs/Grad-ProbAsk/M.1444749486.A.DC7.html

10/13 23:19, , 1F
Ts = 0
10/13 23:19, 1F

10/13 23:23, , 2F
dQ/dt = A. is just for convenient expression
10/13 23:23, 2F

10/14 00:57, , 3F
好的,謝謝您
10/14 00:57, 3F

10/14 08:42, , 4F
好強~
10/14 08:42, 4F
文章代碼(AID): #1M7I2kt7 (Grad-ProbAsk)
文章代碼(AID): #1M7I2kt7 (Grad-ProbAsk)