Re: [理工] 拉式轉換
※ 引述《xoo1208 (RaInBoW)》之銘言：
: 求此題拉式轉換
: https://www.dropbox.com/s/7e67yfkg24kj95b/Questions.jpg?m
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cos(at)-cosh(at) ---> s/(s^2+a^2) - s/(s^2-a^2)
(1/t)*{cos(at)-cosh(at)} ---> ∫{u/(u^2+a^2) - u/(u^2-a^2)}du
∫(1/t)*{cos(at)-cosh(at)}dt ---> (1/s)*∫{u/(u^2+a^2) - u/(u^2-a^2)}du
(0→t) (s→∞)
積出來 = -( 1/2s )ln{ 1 + ( 2a^2/s^2-a^2 ) }
應該是這樣吧，有錯請指證!
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◆ From: 111.184.227.101
※ 編輯: gnsh 來自: 111.184.227.101 (09/17 02:12)
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