Re: [理工] 常係數線性ODE
※ 引述《xoo1208 (RaInBoW)》之銘言:
: Solve : d^2y/dt^2 - 4dy/dt + 4y = 3e^-t + 2t^2 + sint
: 求解 Yp =
1/(D-2)^2 (3e^(-t)) = 3e^(-t)/9 = (1/3)e^(-t)
1/(D-2)^2 2t^2 = [1/4 + D/4 + 3D^2/16]2t^2 = t^2/2 + t + 3/4
3sint + 4cost
1/(D-2)^2 sin(t) = ------------------
3^2 + 4^2
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08/09 00:39, , 1F
08/09 00:39, 1F
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