Re: [理工] [線代] 96成大資工
※ 引述《Eggchun (阿蛋)》之銘言:
: http://ppt.cc/8G7v
: 我想問第4題...
: 不是用動態系統去解嗎>"<???
: 我算出的eigenvalue為{0,0,0}
: 可是只求出一個eigenvector為 [-1 0 1]^t
: 請問是哪裡算錯了嗎???
: 還是這題不是這樣解~"~
: 麻煩大家幫忙!!
: 謝謝!!
[y1'] [ 1 1 1 ][y1]
[y2']=[ 1 0 1 ][y2] , y1(0)=1, y2(0)=1, y3(0)=-1
[y3'] [-1 -1 -1][y3]
y1'=y1+y2+y3
y2'=y1+y3
y3'=-(y1+y2+y3)
=>
(y1+y3)'=0
又
y2'=y1+y3
所以
y2''=0 => y2=c1x+c2 ...(1)
y1'=y1+y2+y3
=y2'+y2
=c1x+c1+c2
=>
y1=0.5*c1x^2+(c1+c2)x+c3 ...(2)
因為 y2'=y1+y3
所以 y3=y2'-y1
=-0.5*c1x^2-(c1+c2)x+c1-c3...(3)
得
y1=0.5*c1x^2+(c1+c2)x+c3
y2=c1x+c2
y3=-0.5*c1x^2-(c1+c2)x+c1-c3
且
y1(0)=1, y2(0)=1, y3(0)=-1
故
c3=1 ,c2=1, c1-c3=-1
=>
c1=0 ,c2=1 c3=1
=>
y1=x+1
y2=1
y3=-x-1
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※ 編輯: jack0711 來自: 140.113.123.237 (02/24 02:14)
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