Re: [理工][電子]電流鏡
先求出k
k1 = k3 = 2
k2 = 1
假設 M1 = M2 VGS相同
故Io = Ii(k1/k2) = 2Ii ------(1)
5 - 2VGS
而Ii = ---------- --------(2)
2
(1) (2)式聯立 可得 VGS = 1.5V (負不合)
所以 Io = 2mA, Ii = 1mA, Vy = 1.5V, Vx = 3V
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