Re: [理工] [工數]-電機線代
※ 引述《BenLinus (班)》之銘言:
: L(1) = 0 - 0 + 1 = 1
: L(x-1) = 0 - 1 + (x-1) = x-2
: 2 2 2 2
: L((x-1)) = 2x - (2x-2) + (x -2x + 1) = 3x - 4x + 3
: 2
: 再運算一下 1(1) + 0(x-2) + 0(x-2) = 1
: 2
: 0(1) + 1(x-2) + 0(x-2) = x-2
: 2 2
: 7(1) + 8(x-2) + 3(x-2) = 3x - 4x + 3
第三個這邊我是算4(1) + 2(x-2) + 3(x-2)^2
有人跟我算一樣嗎?
: [1 0 7]
: 所以 M = [0 1 8]
: [0 0 3]
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