Re: [理工] [自控]-穩態響應
※ 引述《kobe089 (wei)》之銘言：
: what is the steady-state response y(t) if the input u(t)=2sin(t)?
: Y(s) 1
: — = G(s)= ————
: u(s) s^2+2s+1
: 這題我怎樣算答案都是０
: 可是解答是 sin(t-90度)
: 是我錯了嗎?
: 麻煩各位 謝謝
1 1
|G(jw)| = |-------------| = ---
w=1 (-1)+(2j)+1 2
1 -π
∠G(jw)| = ∠---- = -----
w=1 2j 2
y(t)= 2*|G(jw)|*sin(t+∠G(jw))
1 π π
= 2*---*sin(t - ---) =sin(t - ---)
2 2 2
--
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