Re: [理工] [工數]-一個很笨的微積分問題...
1
u = -------
cosy
-1
對x微 du d(cosy ) dy
======> -- = ------ * ---
dx dy dx
-1
d(cosy ) d(cosy)
======>u' = ------- * ------- * y' (chain rule)
d(cosy) dy
siny
=======> u' = ----------y'
(cosy)^2
--
--
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06/19 00:03, , 1F
06/19 00:03, 1F
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