[理工] [線代]-正交對角化
不知道未啥鬼打牆,我突然算不出來...
A=[13 -4 2]
[-4 13 -2]
[2 -2 10]
λ=9 , 9 ,18
[-1] [1] 單範後 [-1/√5] [1/√2]
λ=9對應的eigenvector= [ 0] [1] ------->[ 0 ] [1/√2]
[ 2],[0] [2/√5 ] , [ 0 ]
[ 2] 單範後 [2/3 ]
λ=18對應的eigenvector= [-2]--------> [-2/3]
[ 1] [1/3 ]
T
A=[-1/√5 1/√2 2/3 ][9 0 0] [-1/√5 1/√2 2/3 ]
[ 0 1/√2 -2/3 ][0 9 0] [ 0 1/√2 -2/3 ]
[2/√5 0 1/3 ][0 0 18] [2/√5 0 1/3 ]
T
問題是 P和P 相乘怎麼不是I,不是說對稱的矩陣可以做正交對角化嗎?
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