Re: [商管] [統計]-機率分配
※ 引述《doremi987 (抖雷咪)》之銘言：
: The probability that the sum of 10 independent
: uniform (0,1) random variable exceeds 6 is approximalely?
: 請問一下這題要如何計算呢?
: 謝謝
Let r.v x~U(0,1)
Z = x - E(x) / [V(x)]^1/2
= (x - 1/2) / (1/12)^1/2
Then,
x = (1/12)^1/2 * Z + 1/2
=> x1+x2+...+x10 = (1/12)^1/2 * 10Z + 5 ,where Z ~ N(0,1)
x1+x2+...+x10 ~ N(5, 10*(1/12)^1/2)
Answer = P(x1+...+x10 > 6)
= P(Z > (6-5)/10*(1/12)^1/2)
(check table)
不確定對不對
個人想法 供作參考
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02/20 11:07, , 1F
02/20 11:07, 1F
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