[理工] [工數]-fourier轉換
求f(x)的fourier轉換
0 x>0
f(x) = e^axH(-x) =〈 ,a>0
e^ax x<0
∞ 0 1
解答為 F(f(x)) = ∫ e^axH(-x)dx =∫ (e^ax)(e^-iwx)dx = -----
-∞ -∞ a-iw
↑
問題是這一步怎麼積?
積完代上下限好像會發散@@
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