Re: [理工] [工數]-拉普拉斯反轉換
※ 引述《Dusuren ()》之銘言：
: F(S)=ln(s^2+1 )-2ln(s-1)
: 求反轉換
: 感謝版友解答
- d F(S)
L[tf(t)]= ________
ds
dF(S)
L^-1[ _______ ] = -tf(t)
ds
2s - 2
L^-1[ ------- + ------ ] = 2cost - 2 e^t = -tf(t)
s^2+1 s-1
2
f(t) = ---(e^t - cost)
t
--
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