Re: [理工] [OS]-DISK
※ 引述《yesa315 (XD)》之銘言：
: http://www.lib.nctu.edu.tw/n_exam/exam93/cis/cis136.pdf
: 這是93交大資科的考題
: 其中第22題 有人可以告訴我這題目的意思嗎
: 答案是 (B) 3
: 謝謝!
trnasfer speed : 100 Mbps => 12.5 MB/sec
rotation speed : 600 rpm => (1/600)*60 = 0.1 seconds per rotation
1200 blocks , 4KB each , per track => 4.8 MB per track
speed of reading blocks under the disk head = 4.8/0.1 = 48 MB/sec
bottleneck is the transfer speed
4KB / (12.5 MB/sec) = 0.32 ms
0.32*10^-3 * 48 = 15.36 KB
15.36 KB / 4 KB = 3.84 取整數 4
4個blocks中扣掉第一個block => 3 blocks
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※ 編輯: svanavs 來自: 60.198.131.51 (09/15 01:25)
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