[問卦] 肥宅從101跳下去是有多快著地?消失
餓死抬頭
先假設一層樓約3公尺 g=9.8 m/s^2
根據自由落體公式H=1/2*g*t^2
從101跳下去的時間為
101*3 = 1/2*9.8*t^2
移項並簡略後得 t=7.863 sec 左右
上述為一般算法
如今題目改成肥宅從101上面跳下來
那麼肥宅跳下來的時間會小於7.863 sec 嗎?
要如何證明?
感覺題目不夠嚴謹(對肥宅的定義)
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需要用到流力概念? 那麼熱力可能也需要 計算熱能損耗比
※ 編輯: processor (111.243.101.73), 04/23/2017 23:27:42
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