Re: [計量] 印度網站的Q 數題

看板GRE作者 (VICTORIA)時間16年前 (2009/05/29 19:34), 編輯推噓0(002)
留言2則, 2人參與, 最新討論串4/4 (看更多)
我想您第二題好像有點錯耶 12=(x-3)*n+5, x & n must be positive then, 7=(x-3)*n, and (x-3) could be 1 or 7 thereby, x=4 or 10 right? ※ 引述《ckyoung (小土)》之銘言: : 補兩題 : : In a company, there are 54 members. If Wednesday has more number of birthdays : : than on any other day of the week, then : : Col A: The least number of birthdays on Wednesday : : Col B: 8 : : Ans: A : : i do have no idea......... : 54/7 = 7 餘 5 : 因此要至少 9人 才會最多 : : Given that there are 'x' boxes and the balls are arranged in such a way that : : no ball is left. If the number of boxes is reduced by 3 and if 12 balls are : : arranged in them, then 5 balls are left behind, what is the original number : : of boxes 'x'? : : i didn't find the answer....... : 12 / (x-3) = ? 餘 5 : 因此 x-3 = 7 : x = 10 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 134.208.22.75

05/31 14:59, , 1F
(x-3)要大於五喔
05/31 14:59, 1F

06/03 10:18, , 2F
n是一盒規定裝多少,如果n是7,x-3當然可以低於5
06/03 10:18, 2F
文章代碼(AID): #1A7yX587 (GRE)
文章代碼(AID): #1A7yX587 (GRE)