Re: [考題] 102年關務 資料結構
不好意思想請教有考關務三等資訊處理的各位~
這題大家的分數都多少?這題正確的答案應該是什麼呢?
因為我朋友回了(D)(E)(F)
結果這題拿了0分!他很不能理解XD 問我我也不太知道 :(
我想到當初PTT有在討論~所以想請問各位大大~
煩請幫忙解答一下
謝謝大家!!!
(PS:因為他租的地方沒有網路所以請我代問一下)
※ 引述《meya (落寞之心)》之銘言:
: ※ 引述《asdd (我愛胖穎穎)》之銘言:
: : 下列哪兩個敘述是錯的
: : (A)0.5n^2+100n=O(n^2) (B)1000=O(1) (C)0.5n+5logn=O(n^2)
: : (D)2n^2+5^n=O(2^n) (E)n^7+1.5^n=O(n^7) (F)3n^2+nlog^4 n=O(nlog^4 n)
: : 請問這題大家怎麼選?我個人覺得(D) (E) (F)都錯 可是題目只要兩個.....
: (D)感謝各位大大指正,此題不能用羅比達
: 2^n 2 n
: lim _______ = lim ( ___ ) = 0
: n→∞ 5^n n→∞ 5
: 所以2^n = o(5^n),可推得2^n = O(5^n)
: 5^n 5 n
: lim ____ = lim ( ___ ) = ∞
: n→∞ 2^n n→∞ 2
: 所以5^n = ω(2^n),可推得5^n = Ω(2^n),(D)是錯的
: (E)感謝各位大大指正
: n^7 7* n^6
: lim _____ = lim ______________ = ... =
: n→∞ 1.5^n n→∞ 1.5^n * ln1.5
: 7*6*5*4*3*2*1 n^0
: ________________ lim _______ = 0
: ln^7 1.5 n→∞ 1.5^n
: 所以n^7 = o(1.5^n),可推得n^7 = O(1.5^n),(E)是錯的
: (F)
: nlog^4 n log^4 n 4*(1/n) log^3 n
: lim __________ = lim ________ = lim _______________ = ... =
: n→∞ 3* n^2 n→∞ 3* n^1 n→∞ 3* n^0
: 4*3*2*1* log^0 n
: lim __________________ = 0
: n→∞ 3* n^1
: 所以nlog^4 n = o(3* n^2),可推得nlog^4 n = O(3* n^2),(F)是錯的
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